I perhaps can help you with this. I'm working in a company that is helping smallholder farmers over the world to increase their crop yield. We used to start with a small hydropowered waterwheel but moved to solar due to the reach of the sun. I am the technical person that is sourcing pumps, solar panels, inverters etc for irrigation.
So far as I can read your question you don't need a lot of water and also not a lot of pressure. It is quite easy to calculate.
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Hydraulic power need (W) / efficiencies = electric power requirement (W)-> *1.3 = solar panel (Wp)
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Hydraulic power = 9,81 * height differencence of water (m) * liter per second you want to pump
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Efficiencies = centrifugal pumps are approx 35% eff so (hydraulicp/0,35) *1,33= panelsize
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halve a liter per second is sufficient for halve an acre (2020m2) of crops.
Please if you have more questions I would glad to be of help