this post was submitted on 07 Aug 2023
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Linux

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I have been working on my scripts for user/group permissions today. This idea has been on my back burner for awhile. I'm sure others have done this before. I just haven't encountered them yet.

I was thinking of just trying to find the flags where they start a line and put everything in a string array until the next line that starts with a flag. Then I would just call the script with the command, a loop would match the flags and print the matches.

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[–] [email protected] 15 points 1 year ago (3 children)
[–] [email protected] 3 points 1 year ago

Inspired by explainshell, I wrote a script (https://github.com/learnbyexample/command_help) to be used from the terminal itself. It is a bit buggy, but works well most of the time. For example:

$ ch grep -Ao
       grep - print lines that match patterns

       -A NUM, --after-context=NUM
              Print NUM lines of trailing context after matching lines.  Places a
              line containing a group separator (--) between contiguous groups of
              matches.  With the -o or --only-matching option, this has no effect
              and a warning is given.

       -o, --only-matching
              Print  only  the matched (non-empty) parts of a matching line, with
              each such part on a separate output line.
[–] [email protected] 2 points 1 year ago

omg that is lovely. Kinda like https://regex101.com/ for regular expressions.

[–] [email protected] 4 points 1 year ago

I like to use cht.sh you it maps it's subdirectories to commands and you just curl it.

Eg:

curl cht.sh/cat curl cht.sh/grep

[–] [email protected] 2 points 1 year ago

you're probably looking for getopt/getopts. one big difference between them is getopt handles --long options while getopt doesn't.

other example