In the spirit of Lemmy/federation giving more power to the users. I want to let the users of this community vote on our first candidate for a new mod. This is a little risky because there has not been much time for community to form, but I think its a chance to set a good precedence.
Voter information
The candidate for a new mod: lemmy.world/u/forkball
My arguments for adding them as a mod:
- Assuming its the same person, reddit.com/u/forkball was an active reddit user since 2011. And from briefly scanning their history on reddit and Lemmy, they seem like a good level headed person. I think they would be a good mod, but the voice of the community is what matters.
- I have no mod experience and was always a complete reddit lurker, so it would be good to have a very active community member as a mod.
My arguments for not adding them:
- Y'all are chill and not causing a lot of work for me. So at this instant I can handle the work load. Not sure how long that will last though.
How to place a vote
I hope to avoid bots so voting will take some effort.
To place a vote you must comment on this post (I wont count nested comments). Your comment must begin with "YES:" or "NO:" followed by no less than 4 words justifying your vote.
Votes must be submitted before June 29 at 06:00 UTC.
If we have more YES votes than NO votes, u/forkball will become a mod.
Here are examples of valid voting comments: "YES: because forkball both showers and thinks!" "NO: because they didn't give me an up doot"
Fineprint
Lemmy and moderating is still new to me so if this ends up being a really dumb move on my part for some reason I cannot foresee, I reserve the right to bail on this idea and try another method for community input. Things would need to get really nuts for me to bail on this vote.
I don't expect a huge number of votes, but if im wrong, it may take some time to tally the votes.
Edits
- It seems implied, but only one vote per username. Feel free to report duplicates. I will also try to publish the counted votes so people can validate my tally.