this post was submitted on 20 Jun 2024
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[โ€“] [email protected] 42 points 4 months ago* (last edited 4 months ago) (1 children)

python -c 'print((61966753*385408813*916167677<<2).to_bytes(11).decode())'

how?

$ python
>>> b"Hello World".hex()
'48656c6c6f20576f726c64'
>>> 0x48656c6c6f20576f726c64
87521618088882533792115812
$ factor 87521618088882533792115812
87521618088882533792115812: 2 2 61966753 385408813 916167677

[โ€“] [email protected] 21 points 4 months ago

perl -le 'use bignum;print+pack"H22",(61966753*385408813*916167677<<2)->to_hex()'

Alas, Perl doesn't bignum by default