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Beethoven's 9th Symphony (sh.itjust.works)

submitted 5 months ago by [email protected] to c/[email protected]

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[–] [email protected] 1 points 5 months ago* (last edited 5 months ago)

yup, but that answer was based entirely on the assumptions present in the question. D is all divisible work, and C is everything else, because that's literally all you can assume to make the math work. D has to therefore be 12 months worth of divisible work minus C. C could very well be 12 months of work, meaning D is zero and adding more workers won't matter.