this post was submitted on 24 May 2024
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Statically Typed Functional Programming with Python 3.12 (wickstrom.tech)
submitted 5 months ago by [email protected] to c/[email protected]
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Neato

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[–] [email protected] 3 points 5 months ago* (last edited 5 months ago) (1 children)

You're still limited by lambda expressions though. And in general the language is still statement based, not expression based. You can't do a = if foo then x else y type things (except for the one-off and backwards x if foo else y; they were so close!).

[–] [email protected] 2 points 5 months ago (1 children)

"a = x if foo else y" is a perfectly cromulent statement!

[–] [email protected] 2 points 5 months ago (1 children)

It's not. In functional languages there's no special case like this. All if-elses are expressions. It's far superior. For example how do you do this with Python's if-else expression?

let x = if foo {
  let y = bar();
  baz();
  y
} else {
  z
}
[–] [email protected] 1 points 5 months ago (1 children)

x = foo(y:=bar(), baz(), y) or z should work assuming foo bar and baz are functions being called?

if this is setting y to the effect of bar() + running baz after, then:

x = [bar(), baz()][0] or z

might work

and if you need y to be defined for later use:

x = [(y:=bar()), baz()][0] or z

but thats from memory, not sure if that will even run as written.

if I get to a real computer I'll try that with an actual if statement instead of a bastardized ternary.
[–] [email protected] 2 points 5 months ago (1 children)

foo isn't a function, it's a bool. But in any case, as you can see the answer is "with terrible hacks". Python is not a functional language. It is imperative.

[–] [email protected] 2 points 5 months ago

Yeah, never said it was, just that if you really want to emulate that style you mostly can.